what is the magnitude of the resultant of a 100-newton force along the x-axis and a 150-new2ton force at an angle of 40 degrees to each other

Answer:235.54 NStep-by-step explanation:Since this is an addition of vectors, we need to find the components of each in the x-y plane. Given that the first vector (100 N) is along the x axis, it consist of just x component of size: 100N. For the second vector, its x-component will be given by the cosine projection on the x axis via:x-component [tex]=150*cos(40^o)=114.9[/tex]and its y-component will be given by the "sine" projection: y component [tex]=150*sin(40)=96.42[/tex]Therefore the addition of the x-components for the final vector is:100N + 114.9N = 214.9 NNow we use the Pythagorean theorem to find the magnitude of the resultant addition of vectors: [tex]\sqrt{96.42^2+214.9^2} =\sqrt{55478.8264} =235.54 N[/tex]